4(v+4)=-2(6v-9)+2v

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Solution for 4(v+4)=-2(6v-9)+2v equation: 



4(v+4)=-2(6v-9)+2v

We move all terms to the left:

4(v+4)-(-2(6v-9)+2v)=0

We multiply parentheses

4v-(-2(6v-9)+2v)+16=0



We calculate terms in parentheses: -(-2(6v-9)+2v), so:

-2(6v-9)+2v

We add all the numbers together, and all the variables

2v-2(6v-9)

We multiply parentheses

2v-12v+18

We add all the numbers together, and all the variables

-10v+18

Back to the equation:

-(-10v+18)



We get rid of parentheses

4v+10v-18+16=0

We add all the numbers together, and all the variables

14v-2=0

We move all terms containing v to the left, all other terms to the right

14v=2

v=2/14

v=1/7

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