4(v+4)-v=2(v-1)+9

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Solution for 4(v+4)-v=2(v-1)+9 equation: 



4(v+4)-v=2(v-1)+9

We move all terms to the left:

4(v+4)-v-(2(v-1)+9)=0

We add all the numbers together, and all the variables

-1v+4(v+4)-(2(v-1)+9)=0

We multiply parentheses

-1v+4v-(2(v-1)+9)+16=0



We calculate terms in parentheses: -(2(v-1)+9), so:

2(v-1)+9

We multiply parentheses

2v-2+9

We add all the numbers together, and all the variables

2v+7

Back to the equation:

-(2v+7)



We add all the numbers together, and all the variables

3v-(2v+7)+16=0

We get rid of parentheses

3v-2v-7+16=0

We add all the numbers together, and all the variables

v+9=0

We move all terms containing v to the left, all other terms to the right

v=-9

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