4(v+3)=9v-23

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Solution for 4(v+3)=9v-23 equation: 



4(v+3)=9v-23

We move all terms to the left:

4(v+3)-(9v-23)=0

We multiply parentheses

4v-(9v-23)+12=0

We get rid of parentheses

4v-9v+23+12=0

We add all the numbers together, and all the variables

-5v+35=0

We move all terms containing v to the left, all other terms to the right

-5v=-35

v=-35/-5

v=+7

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