4(v+3)=9v+32

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Solution for 4(v+3)=9v+32 equation: 



4(v+3)=9v+32

We move all terms to the left:

4(v+3)-(9v+32)=0

We multiply parentheses

4v-(9v+32)+12=0

We get rid of parentheses

4v-9v-32+12=0

We add all the numbers together, and all the variables

-5v-20=0

We move all terms containing v to the left, all other terms to the right

-5v=20

v=20/-5

v=-4

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