4(v+3)=-2(8v-3)+2v

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Solution for 4(v+3)=-2(8v-3)+2v equation: 



4(v+3)=-2(8v-3)+2v

We move all terms to the left:

4(v+3)-(-2(8v-3)+2v)=0

We multiply parentheses

4v-(-2(8v-3)+2v)+12=0



We calculate terms in parentheses: -(-2(8v-3)+2v), so:

-2(8v-3)+2v

We add all the numbers together, and all the variables

2v-2(8v-3)

We multiply parentheses

2v-16v+6

We add all the numbers together, and all the variables

-14v+6

Back to the equation:

-(-14v+6)



We get rid of parentheses

4v+14v-6+12=0

We add all the numbers together, and all the variables

18v+6=0

We move all terms containing v to the left, all other terms to the right

18v=-6

v=-6/18

v=-1/3

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