4(v+3)+6v=32

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Solution for 4(v+3)+6v=32 equation: 



4(v+3)+6v=32

We move all terms to the left:

4(v+3)+6v-(32)=0

We add all the numbers together, and all the variables

6v+4(v+3)-32=0

We multiply parentheses

6v+4v+12-32=0

We add all the numbers together, and all the variables

10v-20=0

We move all terms containing v to the left, all other terms to the right

10v=20

v=20/10

v=2

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