4(v+1)=-2(8v-5)+4v

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Solution for 4(v+1)=-2(8v-5)+4v equation: 



4(v+1)=-2(8v-5)+4v

We move all terms to the left:

4(v+1)-(-2(8v-5)+4v)=0

We multiply parentheses

4v-(-2(8v-5)+4v)+4=0



We calculate terms in parentheses: -(-2(8v-5)+4v), so:

-2(8v-5)+4v

We add all the numbers together, and all the variables

4v-2(8v-5)

We multiply parentheses

4v-16v+10

We add all the numbers together, and all the variables

-12v+10

Back to the equation:

-(-12v+10)



We get rid of parentheses

4v+12v-10+4=0

We add all the numbers together, and all the variables

16v-6=0

We move all terms containing v to the left, all other terms to the right

16v=6

v=6/16

v=3/8

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