4(v+1)-v=3(v-2)+3

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Solution for 4(v+1)-v=3(v-2)+3 equation: 



4(v+1)-v=3(v-2)+3

We move all terms to the left:

4(v+1)-v-(3(v-2)+3)=0

We add all the numbers together, and all the variables

-1v+4(v+1)-(3(v-2)+3)=0

We multiply parentheses

-1v+4v-(3(v-2)+3)+4=0



We calculate terms in parentheses: -(3(v-2)+3), so:

3(v-2)+3

We multiply parentheses

3v-6+3

We add all the numbers together, and all the variables

3v-3

Back to the equation:

-(3v-3)



We add all the numbers together, and all the variables

3v-(3v-3)+4=0

We get rid of parentheses

3v-3v+3+4=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation

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