4(u-4)-1=5(-5u+3)-3u

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Solution for 4(u-4)-1=5(-5u+3)-3u equation: 



4(u-4)-1=5(-5u+3)-3u

We move all terms to the left:

4(u-4)-1-(5(-5u+3)-3u)=0

We multiply parentheses

4u-(5(-5u+3)-3u)-16-1=0



We calculate terms in parentheses: -(5(-5u+3)-3u), so:

5(-5u+3)-3u

We add all the numbers together, and all the variables

-3u+5(-5u+3)

We multiply parentheses

-3u-25u+15

We add all the numbers together, and all the variables

-28u+15

Back to the equation:

-(-28u+15)



We add all the numbers together, and all the variables

4u-(-28u+15)-17=0

We get rid of parentheses

4u+28u-15-17=0

We add all the numbers together, and all the variables

32u-32=0

We move all terms containing u to the left, all other terms to the right

32u=32

u=32/32

u=1

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