4(u+6)=-4(2u-5)+6u

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Solution for 4(u+6)=-4(2u-5)+6u equation: 



4(u+6)=-4(2u-5)+6u

We move all terms to the left:

4(u+6)-(-4(2u-5)+6u)=0

We multiply parentheses

4u-(-4(2u-5)+6u)+24=0



We calculate terms in parentheses: -(-4(2u-5)+6u), so:

-4(2u-5)+6u

We add all the numbers together, and all the variables

6u-4(2u-5)

We multiply parentheses

6u-8u+20

We add all the numbers together, and all the variables

-2u+20

Back to the equation:

-(-2u+20)



We get rid of parentheses

4u+2u-20+24=0

We add all the numbers together, and all the variables

6u+4=0

We move all terms containing u to the left, all other terms to the right

6u=-4

u=-4/6

u=-2/3

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