4(u+4)=-2(2u-3)+2u

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Solution for 4(u+4)=-2(2u-3)+2u equation: 



4(u+4)=-2(2u-3)+2u

We move all terms to the left:

4(u+4)-(-2(2u-3)+2u)=0

We multiply parentheses

4u-(-2(2u-3)+2u)+16=0



We calculate terms in parentheses: -(-2(2u-3)+2u), so:

-2(2u-3)+2u

We add all the numbers together, and all the variables

2u-2(2u-3)

We multiply parentheses

2u-4u+6

We add all the numbers together, and all the variables

-2u+6

Back to the equation:

-(-2u+6)



We get rid of parentheses

4u+2u-6+16=0

We add all the numbers together, and all the variables

6u+10=0

We move all terms containing u to the left, all other terms to the right

6u=-10

u=-10/6

u=-1+2/3

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