4(t0-5)+2=t+3

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Solution for 4(t0-5)+2=t+3 equation: 



4(t0-5)+2=t+3

We move all terms to the left:

4(t0-5)+2-(t+3)=0

We add all the numbers together, and all the variables

4(t-5)-(t+3)+2=0

We multiply parentheses

4t-(t+3)-20+2=0

We get rid of parentheses

4t-t-3-20+2=0

We add all the numbers together, and all the variables

3t-21=0

We move all terms containing t to the left, all other terms to the right

3t=21

t=21/3

t=7

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