4(t-4)+8=4(-2t-5)

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Solution for 4(t-4)+8=4(-2t-5) equation: 



4(t-4)+8=4(-2t-5)

We move all terms to the left:

4(t-4)+8-(4(-2t-5))=0

We multiply parentheses

4t-(4(-2t-5))-16+8=0



We calculate terms in parentheses: -(4(-2t-5)), so:

4(-2t-5)

We multiply parentheses

-8t-20

Back to the equation:

-(-8t-20)



We add all the numbers together, and all the variables

4t-(-8t-20)-8=0

We get rid of parentheses

4t+8t+20-8=0

We add all the numbers together, and all the variables

12t+12=0

We move all terms containing t to the left, all other terms to the right

12t=-12

t=-12/12

t=-1

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