4(t-3)+8t=6(2t+3)-10

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Solution for 4(t-3)+8t=6(2t+3)-10 equation:


Simplifying
4(t + -3) + 8t = 6(2t + 3) + -10

Reorder the terms:
4(-3 + t) + 8t = 6(2t + 3) + -10
(-3 * 4 + t * 4) + 8t = 6(2t + 3) + -10
(-12 + 4t) + 8t = 6(2t + 3) + -10

Combine like terms: 4t + 8t = 12t
-12 + 12t = 6(2t + 3) + -10

Reorder the terms:
-12 + 12t = 6(3 + 2t) + -10
-12 + 12t = (3 * 6 + 2t * 6) + -10
-12 + 12t = (18 + 12t) + -10

Reorder the terms:
-12 + 12t = 18 + -10 + 12t

Combine like terms: 18 + -10 = 8
-12 + 12t = 8 + 12t

Add '-12t' to each side of the equation.
-12 + 12t + -12t = 8 + 12t + -12t

Combine like terms: 12t + -12t = 0
-12 + 0 = 8 + 12t + -12t
-12 = 8 + 12t + -12t

Combine like terms: 12t + -12t = 0
-12 = 8 + 0
-12 = 8

Solving
-12 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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