4(t-3)+8=4(2t-6)=

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Solution for 4(t-3)+8=4(2t-6)= equation: 



4(t-3)+8=4(2t-6)=

We move all terms to the left:

4(t-3)+8-(4(2t-6))=0

We multiply parentheses

4t-(4(2t-6))-12+8=0



We calculate terms in parentheses: -(4(2t-6)), so:

4(2t-6)

We multiply parentheses

8t-24

Back to the equation:

-(8t-24)



We add all the numbers together, and all the variables

4t-(8t-24)-4=0

We get rid of parentheses

4t-8t+24-4=0

We add all the numbers together, and all the variables

-4t+20=0

We move all terms containing t to the left, all other terms to the right

-4t=-20

t=-20/-4

t=+5

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