4(t-12)-3t=8t-23+(t-1)

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Solution for 4(t-12)-3t=8t-23+(t-1) equation: 



4(t-12)-3t=8t-23+(t-1)

We move all terms to the left:

4(t-12)-3t-(8t-23+(t-1))=0

We add all the numbers together, and all the variables

-3t+4(t-12)-(8t-23+(t-1))=0

We multiply parentheses

-3t+4t-(8t-23+(t-1))-48=0



We calculate terms in parentheses: -(8t-23+(t-1)), so:

8t-23+(t-1)

determiningTheFunctionDomain
8t+(t-1)-23

We get rid of parentheses

8t+t-1-23

We add all the numbers together, and all the variables

9t-24

Back to the equation:

-(9t-24)



We add all the numbers together, and all the variables

t-(9t-24)-48=0

We get rid of parentheses

t-9t+24-48=0

We add all the numbers together, and all the variables

-8t-24=0

We move all terms containing t to the left, all other terms to the right

-8t=24

t=24/-8

t=-3

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