4(t+1)=2(t-1)-3

Solution for 4(t+1)=2(t-1)-3 equation:

Simplifying
4(t + 1) = 2(t + -1) + -3

Reorder the terms:
4(1 + t) = 2(t + -1) + -3
(1 * 4 + t * 4) = 2(t + -1) + -3
(4 + 4t) = 2(t + -1) + -3

Reorder the terms:
4 + 4t = 2(-1 + t) + -3
4 + 4t = (-1 * 2 + t * 2) + -3
4 + 4t = (-2 + 2t) + -3

Reorder the terms:
4 + 4t = -2 + -3 + 2t

Combine like terms: -2 + -3 = -5
4 + 4t = -5 + 2t

Solving
4 + 4t = -5 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
4 + 4t + -2t = -5 + 2t + -2t

Combine like terms: 4t + -2t = 2t
4 + 2t = -5 + 2t + -2t

Combine like terms: 2t + -2t = 0
4 + 2t = -5 + 0
4 + 2t = -5

Add '-4' to each side of the equation.
4 + -4 + 2t = -5 + -4

Combine like terms: 4 + -4 = 0
0 + 2t = -5 + -4
2t = -5 + -4

Combine like terms: -5 + -4 = -9
2t = -9

Divide each side by '2'.
t = -4.5

Simplifying
t = -4.5