4(t+1)+3(t-4)=13

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Solution for 4(t+1)+3(t-4)=13 equation:


Simplifying
4(t + 1) + 3(t + -4) = 13

Reorder the terms:
4(1 + t) + 3(t + -4) = 13
(1 * 4 + t * 4) + 3(t + -4) = 13
(4 + 4t) + 3(t + -4) = 13

Reorder the terms:
4 + 4t + 3(-4 + t) = 13
4 + 4t + (-4 * 3 + t * 3) = 13
4 + 4t + (-12 + 3t) = 13

Reorder the terms:
4 + -12 + 4t + 3t = 13

Combine like terms: 4 + -12 = -8
-8 + 4t + 3t = 13

Combine like terms: 4t + 3t = 7t
-8 + 7t = 13

Solving
-8 + 7t = 13

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 7t = 13 + 8

Combine like terms: -8 + 8 = 0
0 + 7t = 13 + 8
7t = 13 + 8

Combine like terms: 13 + 8 = 21
7t = 21

Divide each side by '7'.
t = 3

Simplifying
t = 3

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