4(sinx+1)=6-sinx

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Solution for 4(sinx+1)=6-sinx equation:


Simplifying
4(sinx + 1) = 6 + -1sinx

Reorder the terms:
4(1 + insx) = 6 + -1sinx
(1 * 4 + insx * 4) = 6 + -1sinx
(4 + 4insx) = 6 + -1sinx

Solving
4 + 4insx = 6 + -1insx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add 'insx' to each side of the equation.
4 + 4insx + insx = 6 + -1insx + insx

Combine like terms: 4insx + insx = 5insx
4 + 5insx = 6 + -1insx + insx

Combine like terms: -1insx + insx = 0
4 + 5insx = 6 + 0
4 + 5insx = 6

Add '-4' to each side of the equation.
4 + -4 + 5insx = 6 + -4

Combine like terms: 4 + -4 = 0
0 + 5insx = 6 + -4
5insx = 6 + -4

Combine like terms: 6 + -4 = 2
5insx = 2

Divide each side by '5nsx'.
i = 0.4n-1s-1x-1

Simplifying
i = 0.4n-1s-1x-1

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