4(s-3)-4=4+(2-s)

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Solution for 4(s-3)-4=4+(2-s) equation: 



4(s-3)-4=4+(2-s)

We move all terms to the left:

4(s-3)-4-(4+(2-s))=0

We add all the numbers together, and all the variables

4(s-3)-(4+(-1s+2))-4=0

We multiply parentheses

4s-(4+(-1s+2))-12-4=0



We calculate terms in parentheses: -(4+(-1s+2)), so:

4+(-1s+2)

determiningTheFunctionDomain
(-1s+2)+4

We get rid of parentheses

-1s+2+4

We add all the numbers together, and all the variables

-1s+6

Back to the equation:

-(-1s+6)



We add all the numbers together, and all the variables

4s-(-1s+6)-16=0

We get rid of parentheses

4s+1s-6-16=0

We add all the numbers together, and all the variables

5s-22=0

We move all terms containing s to the left, all other terms to the right

5s=22

s=22/5

s=4+2/5

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