4(s-1)=2(s+6)

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Solution for 4(s-1)=2(s+6) equation: 



4(s-1)=2(s+6)

We move all terms to the left:

4(s-1)-(2(s+6))=0

We multiply parentheses

4s-(2(s+6))-4=0



We calculate terms in parentheses: -(2(s+6)), so:

2(s+6)

We multiply parentheses

2s+12

Back to the equation:

-(2s+12)



We get rid of parentheses

4s-2s-12-4=0

We add all the numbers together, and all the variables

2s-16=0

We move all terms containing s to the left, all other terms to the right

2s=16

s=16/2

s=8

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