4(s-1)-2(s+3)=2(s-1)

Solution for 4(s-1)-2(s+3)=2(s-1) equation:

Simplifying
4(s + -1) + -2(s + 3) = 2(s + -1)

Reorder the terms:
4(-1 + s) + -2(s + 3) = 2(s + -1)
(-1 * 4 + s * 4) + -2(s + 3) = 2(s + -1)
(-4 + 4s) + -2(s + 3) = 2(s + -1)

Reorder the terms:
-4 + 4s + -2(3 + s) = 2(s + -1)
-4 + 4s + (3 * -2 + s * -2) = 2(s + -1)
-4 + 4s + (-6 + -2s) = 2(s + -1)

Reorder the terms:
-4 + -6 + 4s + -2s = 2(s + -1)

Combine like terms: -4 + -6 = -10
-10 + 4s + -2s = 2(s + -1)

Combine like terms: 4s + -2s = 2s
-10 + 2s = 2(s + -1)

Reorder the terms:
-10 + 2s = 2(-1 + s)
-10 + 2s = (-1 * 2 + s * 2)
-10 + 2s = (-2 + 2s)

Add '-2s' to each side of the equation.
-10 + 2s + -2s = -2 + 2s + -2s

Combine like terms: 2s + -2s = 0
-10 + 0 = -2 + 2s + -2s
-10 = -2 + 2s + -2s

Combine like terms: 2s + -2s = 0
-10 = -2 + 0
-10 = -2

Solving
-10 = -2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.