4(r-3)=-2(r+5)+6r

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Solution for 4(r-3)=-2(r+5)+6r equation: 


Simplifying
4(r + -3) = -2(r + 5) + 6r

Reorder the terms:
4(-3 + r) = -2(r + 5) + 6r
(-3 * 4 + r * 4) = -2(r + 5) + 6r
(-12 + 4r) = -2(r + 5) + 6r

Reorder the terms:
-12 + 4r = -2(5 + r) + 6r
-12 + 4r = (5 * -2 + r * -2) + 6r
-12 + 4r = (-10 + -2r) + 6r

Combine like terms: -2r + 6r = 4r
-12 + 4r = -10 + 4r

Add '-4r' to each side of the equation.
-12 + 4r + -4r = -10 + 4r + -4r

Combine like terms: 4r + -4r = 0
-12 + 0 = -10 + 4r + -4r
-12 = -10 + 4r + -4r

Combine like terms: 4r + -4r = 0
-12 = -10 + 0
-12 = -10

Solving
-12 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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