4(r+20)=1/5(20r

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Solution for 4(r+20)=1/5(20r equation: 



4(r+20)=1/5(20r

We move all terms to the left:

4(r+20)-(1/5(20r)=0



Domain of the equation: 520r!=0

r!=0/520

r!=0

r∈R



We multiply parentheses

4r-(1/520r+80=0

We multiply all the terms by the denominator


4r*520r+80-(1=0

We add all the numbers together, and all the variables

4r*520r=0

Wy multiply elements

2080r^2=0

a = 2080; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2080·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{4160}=0$

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