4(r+2)=4(2-2r)r=

Solution for 4(r+2)=4(2-2r)r= equation:

4(r+2)=4(2-2r)r=

We move all terms to the left:

4(r+2)-(4(2-2r)r)=0

We add all the numbers together, and all the variables

4(r+2)-(4(-2r+2)r)=0

We multiply parentheses

4r-(4(-2r+2)r)+8=0


We calculate terms in parentheses: -(4(-2r+2)r), so:

4(-2r+2)r

We multiply parentheses

-8r^2+8r

Back to the equation:

-(-8r^2+8r)


We get rid of parentheses

8r^2-8r+4r+8=0

We add all the numbers together, and all the variables

8r^2-4r+8=0

a = 8; b = -4; c = +8;
Δ = b2-4ac
Δ = -42-4·8·8
Δ = -240
Delta is less than zero, so there is no solution for the equation