4(r+1)=3(2r+1)

Solution for 4(r+1)=3(2r+1) equation:

Simplifying
4(r + 1) = 3(2r + 1)

Reorder the terms:
4(1 + r) = 3(2r + 1)
(1 * 4 + r * 4) = 3(2r + 1)
(4 + 4r) = 3(2r + 1)

Reorder the terms:
4 + 4r = 3(1 + 2r)
4 + 4r = (1 * 3 + 2r * 3)
4 + 4r = (3 + 6r)

Solving
4 + 4r = 3 + 6r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-6r' to each side of the equation.
4 + 4r + -6r = 3 + 6r + -6r

Combine like terms: 4r + -6r = -2r
4 + -2r = 3 + 6r + -6r

Combine like terms: 6r + -6r = 0
4 + -2r = 3 + 0
4 + -2r = 3

Add '-4' to each side of the equation.
4 + -4 + -2r = 3 + -4

Combine like terms: 4 + -4 = 0
0 + -2r = 3 + -4
-2r = 3 + -4

Combine like terms: 3 + -4 = -1
-2r = -1

Divide each side by '-2'.
r = 0.5

Simplifying
r = 0.5