4(r+1)-(3r+5)=2

Solution for 4(r+1)-(3r+5)=2 equation:

Simplifying
4(r + 1) + -1(3r + 5) = 2

Reorder the terms:
4(1 + r) + -1(3r + 5) = 2
(1 * 4 + r * 4) + -1(3r + 5) = 2
(4 + 4r) + -1(3r + 5) = 2

Reorder the terms:
4 + 4r + -1(5 + 3r) = 2
4 + 4r + (5 * -1 + 3r * -1) = 2
4 + 4r + (-5 + -3r) = 2

Reorder the terms:
4 + -5 + 4r + -3r = 2

Combine like terms: 4 + -5 = -1
-1 + 4r + -3r = 2

Combine like terms: 4r + -3r = 1r
-1 + 1r = 2

Solving
-1 + 1r = 2

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 1r = 2 + 1

Combine like terms: -1 + 1 = 0
0 + 1r = 2 + 1
1r = 2 + 1

Combine like terms: 2 + 1 = 3
1r = 3

Divide each side by '1'.
r = 3

Simplifying
r = 3