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4(q-5)-3=2(8-q)+3
We move all terms to the left:
4(q-5)-3-(2(8-q)+3)=0
We add all the numbers together, and all the variables
4(q-5)-(2(-1q+8)+3)-3=0
We multiply parentheses
4q-(2(-1q+8)+3)-20-3=0
We calculate terms in parentheses: -(2(-1q+8)+3), so:We add all the numbers together, and all the variables
2(-1q+8)+3
We multiply parentheses
-2q+16+3
We add all the numbers together, and all the variables
-2q+19
Back to the equation:
-(-2q+19)
4q-(-2q+19)-23=0
We get rid of parentheses
4q+2q-19-23=0
We add all the numbers together, and all the variables
6q-42=0
We move all terms containing q to the left, all other terms to the right
6q=42
q=42/6
q=7
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