4(p+3)+2(p-1)=28

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Solution for 4(p+3)+2(p-1)=28 equation: 



4(p+3)+2(p-1)=28

We move all terms to the left:

4(p+3)+2(p-1)-(28)=0

We multiply parentheses

4p+2p+12-2-28=0

We add all the numbers together, and all the variables

6p-18=0

We move all terms containing p to the left, all other terms to the right

6p=18

p=18/6

p=3

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