4(p+2)-(2-p)-4p=0

Solution for 4(p+2)-(2-p)-4p=0 equation:

Simplifying
4(p + 2) + -1(2 + -1p) + -4p = 0

Reorder the terms:
4(2 + p) + -1(2 + -1p) + -4p = 0
(2 * 4 + p * 4) + -1(2 + -1p) + -4p = 0
(8 + 4p) + -1(2 + -1p) + -4p = 0
8 + 4p + (2 * -1 + -1p * -1) + -4p = 0
8 + 4p + (-2 + 1p) + -4p = 0

Reorder the terms:
8 + -2 + 4p + 1p + -4p = 0

Combine like terms: 8 + -2 = 6
6 + 4p + 1p + -4p = 0

Combine like terms: 4p + 1p = 5p
6 + 5p + -4p = 0

Combine like terms: 5p + -4p = 1p
6 + 1p = 0

Solving
6 + 1p = 0

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 1p = 0 + -6

Combine like terms: 6 + -6 = 0
0 + 1p = 0 + -6
1p = 0 + -6

Combine like terms: 0 + -6 = -6
1p = -6

Divide each side by '1'.
p = -6

Simplifying
p = -6