4(n-5)=2(n+2)

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Solution for 4(n-5)=2(n+2) equation:



4(n-5)=2(n+2)
We move all terms to the left:
4(n-5)-(2(n+2))=0
We multiply parentheses
4n-(2(n+2))-20=0
We calculate terms in parentheses: -(2(n+2)), so:
2(n+2)
We multiply parentheses
2n+4
Back to the equation:
-(2n+4)
We get rid of parentheses
4n-2n-4-20=0
We add all the numbers together, and all the variables
2n-24=0
We move all terms containing n to the left, all other terms to the right
2n=24
n=24/2
n=12

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