4(n-3)=3(n-1)

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Solution for 4(n-3)=3(n-1) equation:


Simplifying
4(n + -3) = 3(n + -1)

Reorder the terms:
4(-3 + n) = 3(n + -1)
(-3 * 4 + n * 4) = 3(n + -1)
(-12 + 4n) = 3(n + -1)

Reorder the terms:
-12 + 4n = 3(-1 + n)
-12 + 4n = (-1 * 3 + n * 3)
-12 + 4n = (-3 + 3n)

Solving
-12 + 4n = -3 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
-12 + 4n + -3n = -3 + 3n + -3n

Combine like terms: 4n + -3n = 1n
-12 + 1n = -3 + 3n + -3n

Combine like terms: 3n + -3n = 0
-12 + 1n = -3 + 0
-12 + 1n = -3

Add '12' to each side of the equation.
-12 + 12 + 1n = -3 + 12

Combine like terms: -12 + 12 = 0
0 + 1n = -3 + 12
1n = -3 + 12

Combine like terms: -3 + 12 = 9
1n = 9

Divide each side by '1'.
n = 9

Simplifying
n = 9

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