4(n-3)=-40+8n

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Solution for 4(n-3)=-40+8n equation: 



4(n-3)=-40+8n

We move all terms to the left:

4(n-3)-(-40+8n)=0

We add all the numbers together, and all the variables

4(n-3)-(8n-40)=0

We multiply parentheses

4n-(8n-40)-12=0

We get rid of parentheses

4n-8n+40-12=0

We add all the numbers together, and all the variables

-4n+28=0

We move all terms containing n to the left, all other terms to the right

-4n=-28

n=-28/-4

n=+7

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