4(n-3)+8(2n-3)=4

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Solution for 4(n-3)+8(2n-3)=4 equation: 



4(n-3)+8(2n-3)=4

We move all terms to the left:

4(n-3)+8(2n-3)-(4)=0

We multiply parentheses

4n+16n-12-24-4=0

We add all the numbers together, and all the variables

20n-40=0

We move all terms containing n to the left, all other terms to the right

20n=40

n=40/20

n=2

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