4(n-3)+2n-4=14

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Solution for 4(n-3)+2n-4=14 equation: 



4(n-3)+2n-4=14

We move all terms to the left:

4(n-3)+2n-4-(14)=0

We add all the numbers together, and all the variables

2n+4(n-3)-18=0

We multiply parentheses

2n+4n-12-18=0

We add all the numbers together, and all the variables

6n-30=0

We move all terms containing n to the left, all other terms to the right

6n=30

n=30/6

n=5

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