4(n-2)-(3-7n)=10n

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Solution for 4(n-2)-(3-7n)=10n equation: 



4(n-2)-(3-7n)=10n

We move all terms to the left:

4(n-2)-(3-7n)-(10n)=0

We add all the numbers together, and all the variables

4(n-2)-(-7n+3)-10n=0

We add all the numbers together, and all the variables

-10n+4(n-2)-(-7n+3)=0

We multiply parentheses

-10n+4n-(-7n+3)-8=0

We get rid of parentheses

-10n+4n+7n-3-8=0

We add all the numbers together, and all the variables

n-11=0

We move all terms containing n to the left, all other terms to the right

n=11

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