4(n-1)-6=-n+5(n-2)

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Solution for 4(n-1)-6=-n+5(n-2) equation: 



4(n-1)-6=-n+5(n-2)

We move all terms to the left:

4(n-1)-6-(-n+5(n-2))=0

We multiply parentheses

4n-(-n+5(n-2))-4-6=0



We calculate terms in parentheses: -(-n+5(n-2)), so:

-n+5(n-2)

We add all the numbers together, and all the variables

-1n+5(n-2)

We multiply parentheses

-1n+5n-10

We add all the numbers together, and all the variables

4n-10

Back to the equation:

-(4n-10)



We add all the numbers together, and all the variables

4n-(4n-10)-10=0

We get rid of parentheses

4n-4n+10-10=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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