4(n-1)-3(n+1)=5(2n-2)-4(3n-1)

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Solution for 4(n-1)-3(n+1)=5(2n-2)-4(3n-1) equation: 



4(n-1)-3(n+1)=5(2n-2)-4(3n-1)

We move all terms to the left:

4(n-1)-3(n+1)-(5(2n-2)-4(3n-1))=0

We multiply parentheses

4n-3n-(5(2n-2)-4(3n-1))-4-3=0



We calculate terms in parentheses: -(5(2n-2)-4(3n-1)), so:

5(2n-2)-4(3n-1)

We multiply parentheses

10n-12n-10+4

We add all the numbers together, and all the variables

-2n-6

Back to the equation:

-(-2n-6)



We add all the numbers together, and all the variables

n-(-2n-6)-7=0

We get rid of parentheses

n+2n+6-7=0

We add all the numbers together, and all the variables

3n-1=0

We move all terms containing n to the left, all other terms to the right

3n=1

n=1/3

n=1/3

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