4(n-1)+n=5(n+4)-6n

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Solution for 4(n-1)+n=5(n+4)-6n equation: 



4(n-1)+n=5(n+4)-6n

We move all terms to the left:

4(n-1)+n-(5(n+4)-6n)=0

We add all the numbers together, and all the variables

n+4(n-1)-(5(n+4)-6n)=0

We multiply parentheses

n+4n-(5(n+4)-6n)-4=0



We calculate terms in parentheses: -(5(n+4)-6n), so:

5(n+4)-6n

We add all the numbers together, and all the variables

-6n+5(n+4)

We multiply parentheses

-6n+5n+20

We add all the numbers together, and all the variables

-1n+20

Back to the equation:

-(-1n+20)



We add all the numbers together, and all the variables

5n-(-1n+20)-4=0

We get rid of parentheses

5n+1n-20-4=0

We add all the numbers together, and all the variables

6n-24=0

We move all terms containing n to the left, all other terms to the right

6n=24

n=24/6

n=4

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