4(n+4)-4=6(n-2)

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Solution for 4(n+4)-4=6(n-2) equation: 



4(n+4)-4=6(n-2)

We move all terms to the left:

4(n+4)-4-(6(n-2))=0

We multiply parentheses

4n-(6(n-2))+16-4=0



We calculate terms in parentheses: -(6(n-2)), so:

6(n-2)

We multiply parentheses

6n-12

Back to the equation:

-(6n-12)



We add all the numbers together, and all the variables

4n-(6n-12)+12=0

We get rid of parentheses

4n-6n+12+12=0

We add all the numbers together, and all the variables

-2n+24=0

We move all terms containing n to the left, all other terms to the right

-2n=-24

n=-24/-2

n=+12

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