4(n+3)=14-3(n-4)

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Solution for 4(n+3)=14-3(n-4) equation: 



4(n+3)=14-3(n-4)

We move all terms to the left:

4(n+3)-(14-3(n-4))=0

We multiply parentheses

4n-(14-3(n-4))+12=0



We calculate terms in parentheses: -(14-3(n-4)), so:

14-3(n-4)

determiningTheFunctionDomain
-3(n-4)+14

We multiply parentheses

-3n+12+14

We add all the numbers together, and all the variables

-3n+26

Back to the equation:

-(-3n+26)



We get rid of parentheses

4n+3n-26+12=0

We add all the numbers together, and all the variables

7n-14=0

We move all terms containing n to the left, all other terms to the right

7n=14

n=14/7

n=2

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