4(n+3)+n-2=30

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Solution for 4(n+3)+n-2=30 equation: 



4(n+3)+n-2=30

We move all terms to the left:

4(n+3)+n-2-(30)=0

We add all the numbers together, and all the variables

n+4(n+3)-32=0

We multiply parentheses

n+4n+12-32=0

We add all the numbers together, and all the variables

5n-20=0

We move all terms containing n to the left, all other terms to the right

5n=20

n=20/5

n=4

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