4(n+3)+32-n=5

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Solution for 4(n+3)+32-n=5 equation: 



4(n+3)+32-n=5

We move all terms to the left:

4(n+3)+32-n-(5)=0

We add all the numbers together, and all the variables

-1n+4(n+3)+27=0

We multiply parentheses

-1n+4n+12+27=0

We add all the numbers together, and all the variables

3n+39=0

We move all terms containing n to the left, all other terms to the right

3n=-39

n=-39/3

n=-13

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