4(n+3)+2(n+8)=40

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Solution for 4(n+3)+2(n+8)=40 equation:


Simplifying
4(n + 3) + 2(n + 8) = 40

Reorder the terms:
4(3 + n) + 2(n + 8) = 40
(3 * 4 + n * 4) + 2(n + 8) = 40
(12 + 4n) + 2(n + 8) = 40

Reorder the terms:
12 + 4n + 2(8 + n) = 40
12 + 4n + (8 * 2 + n * 2) = 40
12 + 4n + (16 + 2n) = 40

Reorder the terms:
12 + 16 + 4n + 2n = 40

Combine like terms: 12 + 16 = 28
28 + 4n + 2n = 40

Combine like terms: 4n + 2n = 6n
28 + 6n = 40

Solving
28 + 6n = 40

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + -28 + 6n = 40 + -28

Combine like terms: 28 + -28 = 0
0 + 6n = 40 + -28
6n = 40 + -28

Combine like terms: 40 + -28 = 12
6n = 12

Divide each side by '6'.
n = 2

Simplifying
n = 2

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