4(n+3)+2(3n+1)=18

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Solution for 4(n+3)+2(3n+1)=18 equation: 



4(n+3)+2(3n+1)=18

We move all terms to the left:

4(n+3)+2(3n+1)-(18)=0

We multiply parentheses

4n+6n+12+2-18=0

We add all the numbers together, and all the variables

10n-4=0

We move all terms containing n to the left, all other terms to the right

10n=4

n=4/10

n=2/5

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