4(n+2)-3(n-1)=17

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Solution for 4(n+2)-3(n-1)=17 equation:


Simplifying
4(n + 2) + -3(n + -1) = 17

Reorder the terms:
4(2 + n) + -3(n + -1) = 17
(2 * 4 + n * 4) + -3(n + -1) = 17
(8 + 4n) + -3(n + -1) = 17

Reorder the terms:
8 + 4n + -3(-1 + n) = 17
8 + 4n + (-1 * -3 + n * -3) = 17
8 + 4n + (3 + -3n) = 17

Reorder the terms:
8 + 3 + 4n + -3n = 17

Combine like terms: 8 + 3 = 11
11 + 4n + -3n = 17

Combine like terms: 4n + -3n = 1n
11 + 1n = 17

Solving
11 + 1n = 17

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 1n = 17 + -11

Combine like terms: 11 + -11 = 0
0 + 1n = 17 + -11
1n = 17 + -11

Combine like terms: 17 + -11 = 6
1n = 6

Divide each side by '1'.
n = 6

Simplifying
n = 6

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