4(n+1)=2(n+5)

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Solution for 4(n+1)=2(n+5) equation:


Simplifying
4(n + 1) = 2(n + 5)

Reorder the terms:
4(1 + n) = 2(n + 5)
(1 * 4 + n * 4) = 2(n + 5)
(4 + 4n) = 2(n + 5)

Reorder the terms:
4 + 4n = 2(5 + n)
4 + 4n = (5 * 2 + n * 2)
4 + 4n = (10 + 2n)

Solving
4 + 4n = 10 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
4 + 4n + -2n = 10 + 2n + -2n

Combine like terms: 4n + -2n = 2n
4 + 2n = 10 + 2n + -2n

Combine like terms: 2n + -2n = 0
4 + 2n = 10 + 0
4 + 2n = 10

Add '-4' to each side of the equation.
4 + -4 + 2n = 10 + -4

Combine like terms: 4 + -4 = 0
0 + 2n = 10 + -4
2n = 10 + -4

Combine like terms: 10 + -4 = 6
2n = 6

Divide each side by '2'.
n = 3

Simplifying
n = 3

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