4(n+1)+1(n+3)=5(n+1)+2

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Solution for 4(n+1)+1(n+3)=5(n+1)+2 equation:


Simplifying
4(n + 1) + 1(n + 3) = 5(n + 1) + 2

Reorder the terms:
4(1 + n) + 1(n + 3) = 5(n + 1) + 2
(1 * 4 + n * 4) + 1(n + 3) = 5(n + 1) + 2
(4 + 4n) + 1(n + 3) = 5(n + 1) + 2

Reorder the terms:
4 + 4n + 1(3 + n) = 5(n + 1) + 2
4 + 4n + (3 * 1 + n * 1) = 5(n + 1) + 2
4 + 4n + (3 + 1n) = 5(n + 1) + 2

Reorder the terms:
4 + 3 + 4n + 1n = 5(n + 1) + 2

Combine like terms: 4 + 3 = 7
7 + 4n + 1n = 5(n + 1) + 2

Combine like terms: 4n + 1n = 5n
7 + 5n = 5(n + 1) + 2

Reorder the terms:
7 + 5n = 5(1 + n) + 2
7 + 5n = (1 * 5 + n * 5) + 2
7 + 5n = (5 + 5n) + 2

Reorder the terms:
7 + 5n = 5 + 2 + 5n

Combine like terms: 5 + 2 = 7
7 + 5n = 7 + 5n

Add '-7' to each side of the equation.
7 + -7 + 5n = 7 + -7 + 5n

Combine like terms: 7 + -7 = 0
0 + 5n = 7 + -7 + 5n
5n = 7 + -7 + 5n

Combine like terms: 7 + -7 = 0
5n = 0 + 5n
5n = 5n

Add '-5n' to each side of the equation.
5n + -5n = 5n + -5n

Combine like terms: 5n + -5n = 0
0 = 5n + -5n

Combine like terms: 5n + -5n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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