4(n+-2)=40-12n

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Solution for 4(n+-2)=40-12n equation: 



4(n+-2)=40-12n

We move all terms to the left:

4(n+-2)-(40-12n)=0

We add all the numbers together, and all the variables

4(n-2)-(-12n+40)=0

We multiply parentheses

4n-(-12n+40)-8=0

We get rid of parentheses

4n+12n-40-8=0

We add all the numbers together, and all the variables

16n-48=0

We move all terms containing n to the left, all other terms to the right

16n=48

n=48/16

n=3

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