4(m-3)=2(6-2m)

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Solution for 4(m-3)=2(6-2m) equation: 



4(m-3)=2(6-2m)

We move all terms to the left:

4(m-3)-(2(6-2m))=0

We add all the numbers together, and all the variables

4(m-3)-(2(-2m+6))=0

We multiply parentheses

4m-(2(-2m+6))-12=0



We calculate terms in parentheses: -(2(-2m+6)), so:

2(-2m+6)

We multiply parentheses

-4m+12

Back to the equation:

-(-4m+12)



We get rid of parentheses

4m+4m-12-12=0

We add all the numbers together, and all the variables

8m-24=0

We move all terms containing m to the left, all other terms to the right

8m=24

m=24/8

m=3

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